x^2-3x=(x+4)(x+5)

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Solution for x^2-3x=(x+4)(x+5) equation: 



x^2-3x=(x+4)(x+5)

We move all terms to the left:

x^2-3x-((x+4)(x+5))=0

We multiply parentheses ..

x^2-((+x^2+5x+4x+20))-3x=0



We calculate terms in parentheses: -((+x^2+5x+4x+20)), so:

(+x^2+5x+4x+20)

We get rid of parentheses

x^2+5x+4x+20

We add all the numbers together, and all the variables

x^2+9x+20

Back to the equation:

-(x^2+9x+20)



We add all the numbers together, and all the variables

x^2-3x-(x^2+9x+20)=0

We get rid of parentheses

x^2-x^2-3x-9x-20=0

We add all the numbers together, and all the variables

-12x-20=0

We move all terms containing x to the left, all other terms to the right

-12x=20

x=20/-12

x=-1+2/3

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